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Support for multiple elements with same data-fragment-index 

When multiple elements are specified with the same data-fragment-index,
they are all shown or hidden at once.
edit
Nigel Stanger 2013-05-02 12:26:23 +12:00
parent 1219564e05
commit 76fce3b4d9
1 changed files with 26 additions and 10 deletions
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28
js/reveal.js
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@ -1629,10 +1629,18 @@ var Reveal = (function(){
var fragments = sortFragments( currentSlide.querySelectorAll( '.fragment:not(.visible)' ) );
if( fragments.length ) {
fragments[0].classList.add( 'visible' );
// There may be multiple fragments with the same index. We want to display all of them.
var nextFragmentIndex = fragments[0].getAttribute( 'data-fragment-index' );
// Notify subscribers of the change
dispatchEvent( 'fragmentshown', { fragment: fragments[0] } );
toArray( fragments ).forEach( function( thisFragment ) {
var f = thisFragment.getAttribute( 'data-fragment-index' );
if( f === nextFragmentIndex ) {
thisFragment.classList.add( 'visible' );
// Notify subscribers of the change
dispatchEvent( 'fragmentshown', { fragment: thisFragment } );
}
} );
updateControls();
return true;
@ -1655,10 +1663,18 @@ var Reveal = (function(){
var fragments = sortFragments( currentSlide.querySelectorAll( '.fragment.visible' ) );
if( fragments.length ) {
fragments[ fragments.length - 1 ].classList.remove( 'visible' );
// There may be multiple fragments with the same index. We want to display all of them.
var prevFragmentIndex = fragments[0].getAttribute( 'data-fragment-index' );
// Notify subscribers of the change
dispatchEvent( 'fragmenthidden', { fragment: fragments[ fragments.length - 1 ] } );
toArray( fragments ).forEach( function( thisFragment ) {
var f = thisFragment.getAttribute( 'data-fragment-index' );
if( f === prevFragmentIndex ) {
thisFragment.classList.remove( 'visible' );
// Notify subscribers of the change
dispatchEvent( 'fragmenthidden', { fragment: thisFragment } );
}
} );
updateControls();
return true;